What is the correct impedance of a circuit if eight 16-ohm loudspeakers are connected in parallel?

What is the correct impedance of a circuit if eight 16-ohm loudspeakers are connected in parallel?

• A. 2 ohms
• B. 16 ohms
• C. 6 ohms
• D. 4 ohms

Answer: (A)

To determine the correct impedance of a circuit with eight 16-ohm loudspeakers connected in parallel, it's essential to use the formula for calculating the total impedance (Z) of resistors connected in parallel. The formula for total impedance in parallel connections is: 1/Z = 1/Z1 + 1/Z2 + 1/Z3 + ... + 1/Zn In this case, since all eight loudspeakers have the same impedance of 16 ohms, the formula simplifies to: 1/Z = 8 / 16 This can be calculated as follows: 1/Z = 0.5 (since 8 divided by 16 equals 0.5) To find Z, we take the reciprocal: Z = 1 / (0.5) = 2 ohms Thus, the correct impedance of the circuit when eight 16-ohm loudspeakers are connected in parallel is indeed 2 ohms. This value reflects the decrease in total resistance in a parallel circuit, where adding more pathways (in this case, loudspeakers) reduces the overall impedance.

To determine the correct impedance of a circuit with eight 16-ohm loudspeakers connected in parallel, it's essential to use the formula for calculating the total impedance (Z) of resistors connected in parallel. The formula for total impedance in parallel connections is:

1/Z = 1/Z1 + 1/Z2 + 1/Z3 + ... + 1/Zn

In this case, since all eight loudspeakers have the same impedance of 16 ohms, the formula simplifies to:

1/Z = 8 / 16

This can be calculated as follows:

1/Z = 0.5 (since 8 divided by 16 equals 0.5)

To find Z, we take the reciprocal:

Z = 1 / (0.5) = 2 ohms

Thus, the correct impedance of the circuit when eight 16-ohm loudspeakers are connected in parallel is indeed 2 ohms. This value reflects the decrease in total resistance in a parallel circuit, where adding more pathways (in this case, loudspeakers) reduces the overall impedance.